A body cools from 100 to 90 in 10 minutes and from 90 to 80 in 15 minutes find.the temperature of surrounding is

A body cools from 100 to 90 in 10 minutes and from 90 to 80 in 15 minu

1.	A body cools from 100 to 90 in 10 minutes and from 90 to 80 in 15 minutes find.the temperature of surrounding is
Answer» Let the ROOM TEMPERATURE of be Ф The change in temperature of the BODY from (100 - Ф) to (90 - Ф) is (10 - 2Ф) Thus the cooling rate is : (10 - 2Ф) / 10 From (90 - Ф) to (80 - Ф) we have : (10 - 2Ф) / 15 Equating the two 100 - 20 = 150 - 30Ф 50 = 10Ф Ф = 5°

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A body cools from 100 to 90 in 10 minutes and from 90 to 80 in 15 minutes find.the temperature of surrounding is

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