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A body cools down from `50^(@)C` to `45^(@)C` in 5 minutes and to `40^(@)C` in another 8 minutes. Find the temperature of the surrounding. |
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Answer» Correct Answer - C::D `V = 100CC, Deltatheta = 5^(0) C, T = 5 min` for water `(msDeltatheta)/(dt) = (KA)/l` for kerosene `(ms)/(dt) = (KA)/(l) 1/(Deltatheta)` `implies (100 xx 10^(-3) xx 800 xx 2100)/(t)` `= (100 xx 10^(-3) xx 1000 xx 4200)/(5)` `implies t = (5 xx 800 xx 2100)/(1000 xx 4200) = (2000)/(1000)` |
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