Saved Bookmarks
| 1. |
A body a starts from rest with an acceleration a_(1) . After 2s, another body B starts from rest with an accelerationa_(2). If they travel equal distances in the 5^(th)second after the start of A then, the ratio a_(1) :a_(2)is equal to : |
|
Answer» ` 9 : 7` `S_(5^(th))(A) = S_(3^(th))(B)` `0 + (a_(1))/(2) [(2 xx5)=1] = 0 +(a_(2))/(2) [ (2xx3) - 1]` `(a_(1)xx9)/(2) = (a_(2) xx5)/(2)` `:. (a_(1))/(a_(2)) = (5)/(9)` `a_(1) :a_(2) = 5:9` |
|