1.

A body a starts from rest with an acceleration a_(1) . After 2s, another body B starts from rest with an accelerationa_(2). If they travel equal distances in the 5^(th)second after the start of A then, the ratio a_(1) :a_(2)is equal to :

Answer»

` 9 : 7`
`9 : 5`
`5 : 7`
`5 : 9`

SOLUTION :`S_(n) = u +(a)/(2) (2n-1)`
`S_(5^(th))(A) = S_(3^(th))(B)`
`0 + (a_(1))/(2) [(2 xx5)=1] = 0 +(a_(2))/(2) [ (2xx3) - 1]`
`(a_(1)xx9)/(2) = (a_(2) xx5)/(2)`
`:. (a_(1))/(a_(2)) = (5)/(9)`
`a_(1) :a_(2) = 5:9`


Discussion

No Comment Found