A bob of mass m suspended by a light string oflength L is whirled into a vertical circle as shown figure . What will be the trajectory of the particle , if the string is cut at (a) point B ? (b) point C ? (C ) Point X ?

A bob of mass m suspended by a light string oflength L is whirled into

1.	A bob of mass m suspended by a light string oflength L is whirled into a vertical circle as shown figure . What will be the trajectory of the particle , if the string is cut at (a) point B ? (b) point C ? (C ) Point X ?
Answer» Solution :When bob is WHIRLED into a vertical circle , the REQUIRED centripetal force is equal to the tension in the STRING .When string is cut , tension becomes zero and centripetal force also hence , bob start to move in a straight line path along the direction of its velocity . (a) at point B , the velocity of B is vertically downward , therefore right , therefore,whenstringis cut at C,bob moveshorizontallytowards right . Also , the bob moves under gravity simultaneously with HORIZONTAL uniformspeed . So it traversed on a parabolic path with VERTEX at C. (c) At point X , the velocity of the bob is along the tangent drawn at point X, therefore when stringis cut at pooint C , bob moves along the tangent at that point X . Alsothe bob move under gravity simultaneously with horizontal uniform speed . So , it taversed on a parabolic path with vertex higher than C .