A bob executes shm of period 20 s. Its velocity is found to be 0.05 ms^(-1)after 2 s when it has passed through its mean position. Find the amplitude of the bob.

A bob executes shm of period 20 s. Its velocity is found to be 0.05 ms

1.	A bob executes shm of period 20 s. Its velocity is found to be 0.05 ms^(-1)after 2 s when it has passed through its mean position. Find the amplitude of the bob.
Answer» SOLUTION :`T = 20 s, v=0.05 MS^(-1), t=2 s` `omega = (2PI)/T =2/20 pi = (pi)/10 rad//s` `v = aomega COS omegat` `=0.05 = (api)/10 cos""(pi)/10 xx2 = (pia)/10 cos""pi/5` `0.05 = (pia)/10 xx0.809` `a= (0.05xx10)/(3.14 xx0.809)=0.197m`