1.

A block weight 100n is pushed by a force F on horizontal rough plane moving with acceleration 1m/s ehen force is doubled acceleration becomes 10 then coefficient of friction is

Answer»

Take g = 10m/s^2

Final ANSWER : \mu = 0.8

Steps:
1) Weight = 100 N
=> MG = 100N
=> m = 10 Kg

Let the External Force be F and friction force be f.
Then, according to the Question :
Normal ,N= W = 100 N
F - f = ma \\ => F - \mu N = ma \\ => F - 100 \mu = 10*1 --(1)

2) We know, When Force is doubled, a becomes 10 units.
2F - 100 \mu = ma \\ => 2 F - 100 \mu = 10*10 \\ => 2 F - 100 \mu = 100 ---(2)

3) Solving above equations we get,
\mu =0.8

Hence, COEFFICIENT of friction is 0.8 .


Discussion

No Comment Found

Related InterviewSolutions