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A block of mass m is placed on a horizontal surface. The coefficient of frication between them is `mu`. The block has to be moved by applying a single external force on it. The force may be applied in my direciton. The minimum value of this force must beA. `mg`, applied vertically upward, if `mu gt 1`B. `mumg`, applied horizontally, if `mu lt 1`C. `(mumg)/(sqrt(mu^(2) + 1))` for all values of `mu`D. `(mu^(2)mg)/(mu^(2) +1)` for all values of `mu` |
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Answer» Correct Answer - C |
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