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A block of mass `m` connected to a spring of stiffness `k` is placed on horizontal smooth surface. When block is at `x=0`, spring is in natural length. The block is also subjected to a force `F=(k|x|)/(@)` thenA. Motion of block is SHMB. Time period of motion is `pisqrt((m)/(k))[sqrt(2)+sqrt((2)/(3))]`C. Time period of motion is `pisqrt((m)/(k))[1+sqrt((3)/(2))]`D. Sum of potential energy and kinetic energy of spring block system is maximum at right extreme. |
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Answer» Correct Answer - B::D `k_(eq)=(k)/(2)` for displacement to right `impliesT_(1)=pisqrt((2m)/(k))` `k_(eq)=(3k)/(2)`, for displacement `impliesT_(2)=` `pisqrt((2m)/(3k))` `implies` motion is not `SHM` Time period `T=T_(1)+T_(2)` Work done by F is maximum when block reaches the right extreme |
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