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A block of mass `m` at rest is acted upon by a force `F` for a time t. The kinetic energy of block after time t isA. `(Ft^2)/(m)`B. `(F^2t^2)/(2m)`C. `(Ft^2)/(2m)`D. `(F^2t^2)/(3m)` |
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Answer» Correct Answer - B `a=(F)/(m)` `s=(1)/(2)at^2=(Ft^2)/(2m)` `W=triangleK` `Fs=K-0impliesK=(F^2t^2)/(2m)` |
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