A block of mass m_(2) is placed on a horizontal table and another block of mass m_(1) is placed on top of it. An increasing horizontal force F = at is exerted on the upper block but the lower block never moves as a result. If the co-efficient of friction between the blocks is mu_(1) and that between the lower block and the table is mu_(2), then what is the maximum possible value of mu_(1)//mu_(2)?

A block of mass m_(2) is placed on a horizontal table and another bloc

1.	A block of mass m_(2) is placed on a horizontal table and another block of mass m_(1) is placed on top of it. An increasing horizontal force F = at is exerted on the upper block but the lower block never moves as a result. If the co-efficient of friction between the blocks is mu_(1) and that between the lower block and the table is mu_(2), then what is the maximum possible value of mu_(1)//mu_(2)?
Answer» `m_(2)/(m_(1))` `1+(m_(2))/(m_(1))` `(m_(1))/(m_(2))` `1+(m_(1))/(m_(2))` Solution :`mu_(2)(m_(1)+m_(2))ggtmu_(1)m_(1)g` or,`(m_(1)+m_(2))/(m_(1))GT(mu_(1))/(mu_(2))` or,`(mu_(1))/(mu_(2))LT1+(m_(2))/(m_(1))" ""or",(mu_(1)/mu^(2))_("max")=1+(m_(2))/(m_(1))`