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A block of mass `12 kg` moving on a rough horizontal surface having `(mu_(k) = 0.5, mu_(s) = 0.6)` with a speed `2 m//s` at any instant and a 12 N force is acting opposite to its motion as shown in figure. Friction force acting on the block is A. `72 hat(i) N`B. `-72 hat(i) N`C. `60 hat(i) N`D. `-60 hat(i) N` |
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Answer» Correct Answer - C `f_("max") = mu_(k) N` `= mu_(k) xx 12g` `= 0.5 xx 120` `60 N` since block is in motion kinetic friction acts on it. |
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