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A block of mass 10 kg is to be raised from the bottom to the top of a smooth incline of inclination 30° and length 5m. Work done is 1)245 joule2) 250 joule 3) 240 joule 4) 975 help me out me with this question please please |
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Answer» ▪ Mass of block = 10kg▪ Angle of inclination = 30°▪ Distance covered by block = 5mTo FIND :▪ Work done to raise block from BOTTOM to the top.Concept :✏ This question is completely based on the concept of work-energy theorem.✏ As per WET, ☢ Work done = Change in energyCalculation :☞ If a body of mass m is RAISED through height h, then→ W = mgh→ W = mg(s × sinΦ)→ W = 10×10×5×sin30°→ W = 500/2→ W = 250J (Option-2) |
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