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A block of mass 10 kg is on a rough plane with velocity 10 ms |
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Answer» ass (M) =10KG co–efficient of FRICTION (k) =0.5Horizontal force = 100 Ng = 10m/s2Solution Normal reaction = M* G = 10*= 10Normal reaction = 100NFriction force (F) = k* 0.5 = 0.5 * 100* = 50NF = Ma50 = 10 * aa = 5 m/s2 |
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