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A block of mass `0.50 kg` is moving with a speed of `2.00 cm^(-1)` can a smooth surface . It strikes another mass of `1.00 kg ` and then they move togather as a single body . The energy less charing the collision isA. `0.16 J`B. `1.00 J`C. `0.67 J`D. `0.34 J` |
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Answer» Correct Answer - C (c ) Initial kinetic energy of the system `K.E, = (1)/(2) mu^(2) + (1)/(2) M(0)^(2) = (1)/(2) xx 0.5 xx 2 xx 2 + 0 = 1J` For collision , uppying conservation of linear momentum `m xx u = (m+ M) xx nu ` `:. 0.5 xx 2 = (0.5 +1) xx nu rArr nu = (2)/(3) m//s ` Final kinetic energy of the system is `K.E_(f) = (1)/(2) (m+M) nu^(2) = (1)/(2) (0.5 + 1) xx(2)/(3) xx (2)/(3) = (1)/(3) j` :. Energy loss during collision `= (1 - (1)/(3)) J = 0.67 J` |
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