1.

A block B is pushed momentarily along a horizontal surface with an initial velocity V. If mu is the coefficient of sliding friction between B and the surface, block B will come to rest after a time ?

Answer»

`(g mu)/(V)`
`(g )/(v)`
`(v)/(g)`
`(v)/(g mu)`

SOLUTION :Initialvelocityof ABLOCK= `v_(0)= v`
Finalvelocityv= 0
Now v= `v_(0)+ at`
`0 =v - at`
`a= (0-v)/(t ) =- (v )/(L )`
Nowfrictionforcef= `mu` R= `mu` mg`(:. , R = mg ) `
`:. ,` Retardation- ma = `mu mg`
from equation (1) and (2)
`(v)/( t ) = mu g `(Avoiding-sign)
`t= (v ) /(mu g)`


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