A block at rest explodes into three parts. Two parts start moving alon

1.	A block at rest explodes into three parts. Two parts start moving along X and Y axes respectively with equal speeds of 10 m/s. Find the initial velocity of the third part.
Answer» Thanks for asking the QUESTION! ANSWER:: The block EXPLODED due to its internal energy so , the net external force during this process is 0 . Therefore , centre of mass will not change . Let the body when exploded was at origin of co-ordinate system. If the TWO parts of body having equal masses moving at a SPEED of 10 m/s in POSITIVE x-axis and positive y-axis direction respectively then, √(10² + 10² + 2 x 10 x 10 cos 90°) = 10√2 m/s 45° with respect to positive x-axis And if the centre of mass is at rest then the third part of the body which have equal mass with other two , will move in opposite direction (which is 135° with respect to x-axis) of the resultant at the same velocity. Hope it helps!

A block at rest explodes into three parts. Two parts start moving along X and Y axes respectively with equal speeds of 10 m/s. Find the initial velocity of the third part.

Answer»

Thanks for asking the QUESTION!

ANSWER::

The block EXPLODED due to its internal energy so , the net external force during this process is 0 .

Therefore , centre of mass will not change .

Let the body when exploded was at origin of co-ordinate system.

If the TWO parts of body having equal masses moving at a SPEED of 10 m/s in POSITIVE x-axis and positive y-axis direction respectively then,

√(10² + 10² + 2 x 10 x 10 cos 90°) = 10√2 m/s 45° with respect to positive x-axis

And if the centre of mass is at rest then the third part of the body which have equal mass with other two , will move in opposite direction (which is 135° with respect to x-axis) of the resultant at the same velocity.

Hope it helps!

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