1.

A block A of mass M moving with speed u collides elastically with block B of mass m which is connected to block C of mass m with a spring. When the compression in spring is maximum, the velocity of block C with respect to block A is (Neglect the friction everywhere)

Answer»

ZERO
`(M/(M+m))u`
`(m/(M+m))u`
`(m/M)u`

Solution :`v_(A) = (M-m)/(M+m) u and v_(B) = (2MU)/(M+m)`
Velocity of C at maximum COMPRESSION = `v_(B)/2`
`v_(c) = 1/2[(2M)/(M+m)]u = (M/(M+m))u`
`v_(CA) = v_(C)-v_(A) = (m/(M+m))u`


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