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A black coloured compound `(A)` on reaction with dilute `H_(2)SO_(4)` gives a gas `(B)` which on passing in a solution of an acid `( C)` gives a white turbidity `(D)`.Gas `(B)` when passed in an acidified solution of a compound `(E)` gives a precipitate `(F)` soluble in dilute `HNO_(3)`.After boiling this solution when an excess of `NH_(4)OH` is added a intense blue coloured compound `(G)` is formed. To this solution on addition of acetic acid and aqueous `K_(4)[Fe(CN)_(6)]` a chocolate brown precipitate `(H)` is obtained.On addition of an aqueous solution of `BaCl_(2)` to an aqueous solution of `(E)` a white precipitate insoluble in dilute `HCl` is obtained. Identify the compounds from `(A)` to `(H)`. |
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Answer» Correct Answer - A-`FeS,CuS , PbS, HgS , CoS, NiS` , B-`H_(2)S` , C-`HNO_(3)` D-`S` , E-`CuSO_(4)` , F-`CuS` G-`[Cu(NH_(3))_(4)](NO_(3))_(2)` `CuS+H_(2)SO_(4) to CuSO_(4)+H_(2)S` `2HNO_(3) to 2NO_(2)+H_(2)O+[O]` `H_(2)S+[O]to H_(2)O+S darr ("white")(HNO_(3)` is strong oxidising agent). `CuSO_(4)+H_(2)S to CuS darr +H_(2)SO_(4)` `3CuS + 8HNO_(3) to 3Cu^(2+) + 6NO_(3)^(-)+3S darr +2NO uarr+4H_(2)O.` `2NO_(3)^(2-)+Cu^(2+) +4NH_(4)OH to [Cu(NH_(3))_(4)]^(2+) (NO_(3))_(2)` (intense blue coloured solution )+`4H_(2)O` `[Cu(NH_(3))_(4)(NO_(3))_(2)+K_(4)[Fe(CN)_(6)] to Cu_(2)[Fe(CN)_(6)] darr` (chocolate brown). `Ba^(2+)+CuSO_(4) to BaSO_(4) darr ("white") +Cu^(2+)` |
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