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A bird is tossing (flying to and fro) between two cars moving towards each other on a straight road. One car has a speed of 19 m/h while the other has the speed of 27 km/h. The bird starts moving from first car towards the other and is moving with the speed of 36 km/h and when the two cars were separated by 36 km. What is the total distance covered by the bird? What is the total displacement of the bird? |
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Answer» Let first car be A and second be B, Speed of car A, vA = 18 km/h Speed of car B, vB = 27 km/h Speed of bird, v = 36 km/h Relative speed of cars, vAB = vBA = vA + vB = 45 km/h Initial distance between cars, x = 36 km Time taken by cars to meet, t = \(\frac{x}{v_{AB}}=\frac{36}{45}\) km/h Distance covered by bird in the time, x' = v x t = 36 × 0.8 = 28.8 km Displacement of bird = distance covered by car A in 0.8 h on straight line (because bird starts from car A) ∴ xA = vA x t = 18 × 0.8 = 14.4 km Suppose man is at building A and wants to land on building B. Vertical speed of man, vy = 0 |
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