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A bike starting from rest with a velocity of 72 km per hour over a distance of 40 metres. Calculate is acceleration. |
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Answer» u=0 v=72km/ph or 72*5/18 =20m/sd=40 metres So by third EQUATION of MOTION we get 2as=v^2+u^22*a*40=(20)^2 + 0^280a=400+080a=400a=400/80a=5m/s^2Explanation: |
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