A bicycle starting from rest picks up a velocity of 50m/s over a time

1.	A bicycle starting from rest picks up a velocity of 50m/s over a time period of 10s .Find the acceleration of the bicycle.pls help . PLEASE DONT ANSWERE ANYTHING inappropriate
Answer» ☞Given :- A bicycle starting from REST picks up a VELOCITY of 50m/s over a time period of 10S . ￣￣￣￣￣￣￣￣￣￣￣￣ ☞To Find :- Find the acceleration of the bicycle. ￣￣￣￣￣￣￣￣￣￣￣￣ ☞Formula used :- $a = \frac{<klux>V</klux> - u}{t}$ ￣￣￣￣￣￣￣￣￣￣￣￣ ☞Solution :- v = 50 m/s u = 0 t = 10s First, Applying the formula. $a = \frac{v - u}{t}$ $a = \frac{(50m \: s - 0)}{10}$ $= a = 5m \: s$ So, The acceleration is 5 m/s. ￣￣￣￣￣￣￣￣￣￣￣￣ *Hopes,* *it's* *helpful. ItzNobita5* ^_^

A bicycle starting from rest picks up a velocity of 50m/s over a time period of 10s .Find the acceleration of the bicycle.pls help . PLEASE DONT ANSWERE ANYTHING inappropriate

Answer»

A bicycle starting from REST picks up a VELOCITY of 50m/s over a time period of 10S .

Find the acceleration of the bicycle.

$a = \frac{<klux>V</klux> - u}{t}$

v = 50 m/s

u = 0

t = 10s

Applying the formula.

$a = \frac{v - u}{t}$

$a = \frac{(50m \: s - 0)}{10}$

$= a = 5m \: s$

The acceleration is 5 m/s.

Hopes, it's helpful.