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A beam of helium atoms moves with a velocity 2×10^-4ms^-1.Find the wavelength of particles constituting with the beam. |
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Answer» mis the wavelength of the beam Explanation: ACCORDING to de Broglie's equation λ= h/m×v where, λ=wavelength h=plank '=6.626×10^−34 kgm2/s m=mass Mass of helium ATOM =4amu. Convert amu into KG as follows 4amu× 1g/6.022×10^23amu =0.664×10 ^−23g =6.64×10^−27 kg Putting the values in the above equation as follows. 6.626×10^−34 kgm^2/s /6.64×10^−27 kg×2×10^4m/s =0.498×10^−7m Thus, 0.498×10^−7mis the wavelength of the beam PLEASE MARK ME AS THE BRAINLIEST |
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