A beam of electron accelerated by a large potential difference `V` is mode of strike a metal target of produce X-ray . For which of the following value of `V` , will the resulting X-ray have the lower minimum wavelength?

A beam of electron accelerated by a large potential difference `V` is

1.	A beam of electron accelerated by a large potential difference `V` is mode of strike a metal target of produce X-ray . For which of the following value of `V` , will the resulting X-ray have the lower minimum wavelength?
Answer» Correct Answer - D `lambda_(min) = (hc)/(eV_(max))`

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A beam of electron accelerated by a large potential difference `V` is mode of strike a metal target of produce X-ray . For which of the following value of `V` , will the resulting X-ray have the lower minimum wavelength?

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