A bead of mass ‘m’ is located on a parabolic wire with its axis ve

1.	A bead of mass ‘m’ is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equation is x2 =4ay. The wire frame is fixed and the bead can slide on it without friction. The bead is released from the point y=4a on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by y=a is (Acceleration due to gravity is g)
Answer» A bead of mass ‘m’ is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equation is $x^{2}$ =4ay. The wire frame is fixed and the bead can slide on it without friction. The bead is released from the point $y = 4 a$ on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by $y = a$ is (Acceleration due to gravity is g)

A bead of mass ‘m’ is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equation is x2 =4ay. The wire frame is fixed and the bead can slide on it without friction. The bead is released from the point y=4a on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by y=a is (Acceleration due to gravity is g)

Answer»

A bead of mass ‘m’ is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equation is $x^{2}$ =4ay. The wire frame is fixed and the bead can slide on it without friction. The bead is released from the point $y = 4 a$ on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by $y = a$ is (Acceleration due to gravity is g)

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