A beach ball is inflated to a volume of 25L of air at 15oC. During the afternoon, the volume increases by 1L. What is the new temperature outside?

A beach ball is inflated to a volume of 25L of air at 15oC. During the

1.	A beach ball is inflated to a volume of 25L of air at 15oC. During the afternoon, the volume increases by 1L. What is the new temperature outside?
Answer» EGREE CelsiusExplanation:V1=25 LV2=26 LT1=15+273=288 KV1/T1=V2/T225/288=26/T2T2=26*288/25 =299.52 K =26.52 DEGREE celsiushope it will HELP U : )