1.

A bcc element of density 10m3g/cm^3 has edge length of 314pm.Calculate atomic mass of the element

Answer»

ANSWER: approximately 97

Explanation:

d = 10.3 g/cm^3

a = 314 pm =314 x 10^-10 cm

in CASE of bcc, z = 2

d=M x z / Na {AVOGADRO no} x a^3

M= Na x a^3 x d / z

  = 6.022 x 10^23 x 314 x 10 ^-10 x 10.3 / 2

  = 97.381762 x 10^19

                   



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