A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3

1.	A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω,respectively. How much current would flow through the 12 Ω resistor?[Try to solve these problems and write in your note book)
Answer» Answer: 0.671 A Explanation: There is no current division occurring in a SERIES circuit. Current flow through the component is the same. RESISTANCES are connected in series. Hence, the sum of the resistances will give the value of R. R = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω Potential difference, V = 9 V I = V = 9V = 0.671 A R 13.4Ω ∴ the current that WOULD flow through the 12 Ω resistor will be 0.671 A.

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω,respectively. How much current would flow through the 12 Ω resistor?[Try to solve these problems and write in your note book)

Answer»

Answer:

0.671 A

Explanation:

There is no current division occurring in a SERIES circuit. Current flow through the component is the same.

RESISTANCES are connected in series. Hence, the sum of the resistances will give the value of R. R = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω

Potential difference, V = 9 V

I = V = 9V = 0.671 A

R 13.4Ω

∴ the current that WOULD flow through the 12 Ω resistor will be 0.671 A.

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A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω,respectively. How much current would flow through the 12 Ω resistor?[Try to solve these problems and write in your note book)

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