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A battery of 6 volts is connected ot the termainals of a three meter long wire of uniform thickness and resistance of the order of `100 Omega`. The difference of potential between two points separated by `50 cm` on the wire willA. `1 V`B. `1.5 V`C. `2 V`D. `3 V` |
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Answer» Correct Answer - A (a) Here same current is passing throughout the length of the wire , hence `V prop R prop l` ` implies (V_(1))/(V_(2)) = (l_(1))/(l_(2)) implies (300)/(50) implies V_(2) = 1V` |
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