A bar of cross-section A is subjected to equal and opposite tensile forces F at its ends. Consider a plane through the bar making an angletheta with a plane at right angles to the bar.

A bar of cross-section A is subjected to equal and opposite tensile fo

1.	A bar of cross-section A is subjected to equal and opposite tensile forces F at its ends. Consider a plane through the bar making an angletheta with a plane at right angles to the bar.
Answer» SOLUTION :By definition of bulk modulus, `B_(w)=-V(Deltap)/(DeltaV)=-100xx((100xx1.013xx10^(5)))/((99.5-100))=2.026xx10^(9)N//m^(2)` Now as isothermal elasticity of a gas is equal to its pressure `B_(A)=E_(theta)=p_(0)=1.013xx10^(5)N//m^(2)` So that `(B_(W))/(B_(A))=(C_(A))/(C_(W))=(2.026xx10^(9))/(1.013xx10^(5))=2xx10` [ as C= compressibility `(1)/(B)]` i.e., bulk modulus of water is very large as COMPARED to air. This means that air is about 20,000 times more compressive than water, i.e., the average distance between air molecules is much larger than that between water molecules.