1.

A bar made of iron for which alpha =11xx10^(-6)""^(@)C^(-1) is 10.000 cm at 20^(@)C. At 19^(@)C the length is :

Answer»

`11xx10^(-6) cm` longer
`11xx10^(-6) cm` shorter
`11xx10^(-5)` cm shorter
`11xx10^(-4)` cm shorter

Solution :`Delta l =alpha l Delta T =10 xx10^(-6) 2XX10 cdot 0xx(19-20)`
`Delta l =-11+10^(-5) cm`
-ve sign show that length decreases.
Thus, CORRECT choice is (C ).


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