A balloon starts from the ground with an acceleration of 2m/s^2 , after 5 secs a stone is dropped from the balloon , find the time taken by the rock to reach the ground and the total height attained by the balloon when the rock reaches the ground.

A balloon starts from the ground with an acceleration of 2m/s^2 , afte

1.	A balloon starts from the ground with an acceleration of 2m/s^2 , after 5 secs a stone is dropped from the balloon , find the time taken by the rock to reach the ground and the total height attained by the balloon when the rock reaches the ground.
Answer» v = u + at a = 2 m/s2 t = 5 u = 0 v = 0 + 2*5 = 10 m/s v² = u² + 2as s = v²/2a s = 100/2 s = 50 m Now acceleration of the stone after being dropped is 9.8 m/so u = - 10 m/s s = 50 m g = 9.8 t = 5 s s = it + 1/2 at By solving you will get TIME (t) Hope it helps you. Mark as brainlist if you like answer.

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A balloon starts from the ground with an acceleration of 2m/s^2 , after 5 secs a stone is dropped from the balloon , find the time taken by the rock to reach the ground and the total height attained by the balloon when the rock reaches the ground.

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