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A balloon starts from rest from the ground and moves with uniform acceleration g/8. When it reaches a height h a ball is dropped from it. Find the time taken by the ball to reach the ground. |
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Answer» SOLUTION :Velocity of ballon when is at a height is `v=sqrt((2gh)/(8)=sqrt(gh)/2` `-h=vt-1/2gt^(2)` `-h=sqrt(gh)/2 t-1/2gt^2` `-h=sqrt(gh)/2 t-1/2 gt^(2)` `1/2 gt^(2)-sqrt(gh)/2 t-h=0` SIMPLIFYING and taking only the POSITIVE value as NEGATIVE value of t is not acceptable we get `t=2 sqrt(h/g)` |
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