1.

A balloon is ascending with a velocity of 9.8ms^-1, a sand bag dropped from the balloon when it is at a height of 39.2m from the ground calculate the time taken by bag to reach the ground

Answer»

4sExplanation:velocity of bag,u=velocity of BALLOON in upward direction=9.8m/sas soon as the bag is released 'g' acts in downward directionnow applying S=ut+1/2gt^2-39.2=9.8t+1/2(-9.8)t^2(taking upward as +ve)t^2-2t-8=oon SOLVING t=4,-2accepting +ve value of TSO time TAKEN by bag to REACH ground=4s



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