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A ball thrown vertically upward woth a velocity of 49m/s.Calculate the MAXIMUM HEIGHT it can reach andcalso calculate iys TIME OF FLIGHT. |
Answer» TIME OF FLIGHT = 10sExplanation: u=49 m/sv=0g= -9.8 m/s2gh=v^2-u^22*-9.8*h=-2401h=122.5 mv=u+gt0=49+(-9.8)t-49=-9.8tt=5 secSo TOTAL time=5+5=10 secHOPE IT HELPSMAKE ME BRAINLIEST |
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