1.

A ball thrown vertically upward woth a velocity of 49m/s.Calculate the MAXIMUM HEIGHT it can reach andcalso calculate iys TIME OF FLIGHT.

Answer»

ANSWER:

TIME OF FLIGHT = 10s

Explanation:

u=49 m/s

v=0

g= -9.8 m/s

2gh=v^2-u^2

2*-9.8*h=-2401

h=122.5 m

v=u+gt

0=49+(-9.8)t

-49=-9.8t

t=5 sec

So TOTAL time=5+5=10 sec

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