1.

A ball thrown straight up takes 2.0 sec to reach a height of 40 m. Find (a) its initial speed (b) ots speed at this height and (c) how much higher the ball will go.plz tell fast ​

Answer»

ANSWER:

vf=vi+at  vf=0 a=g =9.8

0=vi+9.8 x2

19.6 +vi

vi =19.6



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