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A ball of weight `W` is supported on a vertical jet of water. If the stream of water flowing from the nozzle has a diameter `D` and velocity `u`, determine the value of `H`. Assume that no loss of energy takes place. |
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Answer» Correct Answer - `1/(2g)` Applying continuity equation at nozzle end at a top position `a_(1)u=a_(2)v` `v=(a_(1)u)/(a_(2))`…..i `v^(2)-u^(2)=-2gH` `implies H=1/(2g) {u^(2)-[W/(rhoa_(1)^(2)u)]^(2)}`…….ii `implies rhoa_(2)v^(2)=Wimplies v=W/(rhoa_(1)u)` `implies (rhoa_(2)u)/W=1/vimpliesv^(2)=W/(rhoa_(1)u)` `impliesH=1/(2g) {u^(2)-[W/(rhoa_(1)^(2)u)]^(2)}` `=1/(2g){u^(2)-[(4D)/(rhopiD^(2)u)]^(2)}` |
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