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A ball of relative density 0.8 falls into water from a height of 2 m. The depth to which the ball will sink is (neglect viscous forces)A. 8 mB. 2 mC. 6 mD. 16 m |
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Answer» Correct Answer - A Velocity of ball just before striking water surface, `v=sqrt(2gh)` or `v=sqrt(4g) m s^(-1) " " (h=2m)` or `a=(V rho_(w)g-Vrho g)/(V rho)=((1-0.8)/(0.8))g=g//4` Now, depth to which ball will sink is `d=(v^(2))/(2a)=(4g)/(2g//4)=8m` |
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