A ball of massm and density rho is immersed in a liquid of density 3rho at a depth h and released. To what height will the ball jump up above the surface of liquid? (neglect the resistance of water and air).

A ball of massm and density rho is immersed in a liquid of density 3rh

1.	A ball of massm and density rho is immersed in a liquid of density 3rho at a depth h and released. To what height will the ball jump up above the surface of liquid? (neglect the resistance of water and air).
Answer» Solution :Volume of ball `V=(m)/(RHO)`, Acceleration of ball INSIDE the liquid `a=(F_("net"))/(m)=("upthrust - weight")/(m)=(((m)/(rho))(3rho)(G)-mg)/(m)` = 2g (upwards) `therefore` velocity of ball while reaching at surface `V=sqrt(2ah)=sqrt(4gh)` `therefore` The ball will jump to a HEIGHT `H=(v^(2))/(2g)=(4gh)/(2g)=2h`