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A ball of mass m is thrown in air with speed `v_(1)` from a height `h_(1)` and it is at a height `h_(2)(gth_(1))` when its speed becomes `v_(2)` . Find the work done on the ball the air resistance. |
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Answer» Work done on the ball by gravity is `W_g=-mg(h_2-h_1)` Let work done on the ball by air resistance be `W_(air)` `:. W_g+W_(air)=DeltaKE` `implies-mg(h_2-h_1)+W_(air)=1/2m(v_2^2-v_1^2)` `implies W_(air)=mg(h_2-h_1)+1/2m(v_2^2-v_1^2)` |
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