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A ball of mass m is pushed down the wall of hemispherical bowl from point A. It just rises up to edge Q of the bowl. Find the speed at which ball is pushed down. |
Answer» Solution :From law of conservation of ENERGY Total energy at A = Total energy at Q `(1)/(2)MV^(2)+mgh=0+mgR` `(1)/(2)mv^(2)=mg(R-h)` `therefore v^(2)=2g(R-h)` or `v=sqrt(2g(R-h))` |
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