A ball of mass m is dropped onto a floor from a certain height. The co

1.	A ball of mass m is dropped onto a floor from a certain height. The collision is perfectly elastic and the ball rebounds to the same height and again falls. Find the average force exerted by the ball on the floor during a long time interval.
Answer» Thanks for ASKING the question! ANSWER:: LET height be 'h' from where the BALL of mass m is DROPPED ONTO a floor. Before collision => v₁ = √(2gh) and then v₁ = 0 After collision => v₂ = - √(2gh) and then v₂ = 0 Rate of change of velocity , F = [m x 2√(2gh)] / t Now , v = √(2gh) , s = h , v = 0 v = u+at √(2gh) = gt t = √(2h/g) Total time = 2√(2h/g) F = [m x 2√(2gh)] / [2√(2h/g) ] = mg Hope it helps!

A ball of mass m is dropped onto a floor from a certain height. The collision is perfectly elastic and the ball rebounds to the same height and again falls. Find the average force exerted by the ball on the floor during a long time interval.

Answer»

Thanks for ASKING the question!

ANSWER::

LET height be 'h' from where the BALL of mass m is DROPPED ONTO a floor.

Before collision => v₁ = √(2gh) and then v₁ = 0

After collision => v₂ = - √(2gh) and then v₂ = 0

Rate of change of velocity , F = [m x 2√(2gh)] / t

Now , v = √(2gh) , s = h , v = 0

v = u+at

√(2gh) = gt

t = √(2h/g)

Total time = 2√(2h/g)

F = [m x 2√(2gh)] / [2√(2h/g) ] = mg

Hope it helps!

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A ball of mass m is dropped onto a floor from a certain height. The collision is perfectly elastic and the ball rebounds to the same height and again falls. Find the average force exerted by the ball on the floor during a long time interval.

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