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a ball of mass 2kg from a height of 5 makers. what is its kinetic energy when huts rashes the ground​

Answer»

{\pink{\underline{\underline{\purple{\textsf{\textbf{Correct question : }}}}}}}

A metal ball of mass 2kg is allowed to fall FREELY from rest from a height of 5m above the ground \rm (Take g=10ms^{−2}). What is the kinetic energy of the ball just before it hits the ground?

{\pink{\underline{\underline{\purple{\textsf{\textbf{Answer : }}}}}}}

➡ 100joule.

{\pink{\underline{\underline{\purple{\textsf{\textbf{Explanation : }}}}}}}

Given that, A ball of mass 2kg is allowed to fall freely from rest to a height of 5metres.

Using the formula :

❃ K. E. (kinetic energy) = mgh

Where,

m (mass) = 2kg

g (acceleration due to gravity) = \rm {10ms}^{2}

H (height) = 5 METRES.

Procedure :

➡ K. E. = mgh

➡ K. E. = 2*5*10

➡ K. E. = 100 joule.

{\pink{\underline{\underline{\purple{\textsf{\textbf{Hence, the kinetic energy of the ball is 100joule. }}}}}}}

{\blue{\underline{\underline{\green{\textsf{\textbf{Additional info : }}}}}}}

This is the total energy as K.E is zero when the ball is at maximum height that is when it is at 5 m. Hence when the ball reaches the ground P.E becomes zero because of zero height.At this point,the total energy is equal to the K.E that is K.E=100J.


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