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A ball of mass 200 gram fall from a height of 5 metre what is its kinetic energy when it reaches the ground (g= 9.8m/sec) |
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Answer» Mass of the ball (m) = 200 gHeight (h) = 5 mAcceleration due to gravity (g) = 9.8 m/s²To Find :kinetic energy of the ball when it reaches the ground = ?Solution :First convert the unit of the mass of ball from gram to kilogram :→ Mass of ball = 200 g→ Mass of ball = (200) ÷ (1000)→ Mass of ball = 2 ÷ 10→ Mass of ball = 0.2 kgHence,the mass of the ball is 0.2 kg.According to the QUESTION Now :Finding potential energy at higest point :→ Potential energy = mass × Acceleration due to gravity × Height→ Potential energy = 0.2 × 9.8 × 5→ Potential energy = 1.96 × 5→ Potential energy = 9.8 JHence,the potential energy of the ball is 9.8 J.As we KNOW that, the Potential energy at the highest point is equal to the Kinetic energy at the lowest point.Hence,from the above STATEMENT we can CONCLUDE that the Kinetic energy of the ball when it reaches the ground will be 9.8 J. |
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