A ball of 100 g mass is moved with 10 m/s, and decreases to 5 m/s in 5

1.	A ball of 100 g mass is moved with 10 m/s, and decreases to 5 m/s in 5 seconds due to air friction, so force of friction due to air is
Answer» $\huge\sf\pink{Answer}$ ☞ Force of air is -0.1 N ━━━━━━━━━━━━━ $\huge\sf\blue{<klux>GIVEN</klux>}$ ✭ Initial Velocity (u) = 10 m/s ✭ Final Velocity (v) = 5 m/s ✭ Mass (m) = 100 g = 100/1000 = 0.1 kg ✭ TIME (t) = 5 sec ━━━━━━━━━━━━━ $\huge\sf\gray{To \:Find}$ ◈ Friction due to air? ━━━━━━━━━━━━━ $\huge\sf\purple{Steps}$ So here we shall use Newton's second LAW of motion, that is, $\underline{\boxed{\sf F=ma}}$ But here first we should find acceleration of the body and to find that we shall use the first EQUATION of motion, that is, $\underline{\boxed{\sf v = u+at}}$ Substituting the given values, ➝ $\sf v = u+at$ ➝ $\sf 5=10+a\times 5$ ➝ $\sf 5-10=5a$ ➝ $\sf -5=5a$ ➝ $\sf \dfrac{-5}{5} = a$ ➝ $\sf \red{a=-1 \ m/s^2}$ So now substitute the required Values in F = ma ➳ $\sf F=ma$ ➳ $\sf F=0.1\times -1$ ➳ $\sf \orange{F=-0.1 \ N}$ ━━━━━━━━━━━━━━━━━━