1.

A ball moving with velocity 2m/s collides head on with another stationaryball of double the mass . If coefficient of restitution is 0.5 then their velocities after collision will be ………. ms^(-1) .

Answer»

0,1
1,1
`1,0.05`
0,2

Solution :Coefficient of restitution ` e = (v_(1)^(.)-v_(2)^(.))/(v_(2)-v_(1))`
` :. 0.5 = (v_(2)-v_(1))/2 `
` :. V_(2) = 1 + v_(1) ""………(1)`
From conservation of momentum
`mv_(1)+2mv_(2)=mv_(1)+2mv_(2),v_(1)=2m//s ND v_(2) = 0 `
` 2m = mv_(1) +2mv_(2) "".....(2)`
From EQUATION (1) and (2)
` :. 2 = v_(1)+2(1+v_(1))`
` :. 2 =v_(1)+2+2v_(1)`
` :. 3v_(1)=0`
` :. v_(1)=0`
From equation (1) `v_(2) =1 ` m/s .


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