Saved Bookmarks
| 1. |
A ball moving with velocity 2m/s collides head on with another stationaryball of double the mass . If coefficient of restitution is 0.5 then their velocities after collision will be ………. ms^(-1) . |
|
Answer» 0,1 ` :. 0.5 = (v_(2)-v_(1))/2 ` ` :. V_(2) = 1 + v_(1) ""………(1)` From conservation of momentum `mv_(1)+2mv_(2)=mv_(1)+2mv_(2),v_(1)=2m//s ND v_(2) = 0 ` ` 2m = mv_(1) +2mv_(2) "".....(2)` From EQUATION (1) and (2) ` :. 2 = v_(1)+2(1+v_(1))` ` :. 2 =v_(1)+2+2v_(1)` ` :. 3v_(1)=0` ` :. v_(1)=0` From equation (1) `v_(2) =1 ` m/s . |
|