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A balL is thrown with a velocity of 12m/s at an elevation angle of 30 from the top Of a tower with height 61m. Find the time taken by it to reach the ground. At what distance from the foot of the to were will it hit the ground? |
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Answer» component of velocity in the vertical-upward direction is, v=50sin(30 0 )=50×0.5=25m/s Let the time TAKEN to reach GROUND from initial position be t sec The acceleration DUE to GRAVITY is, g=10m/s 2 , in the vertical-downward direction. and the DISTANCE traveled is, h=70m, in the vertical-downward direction. So here, h=−vt+ 2 1
gt 2 ⟹70=−25t+(0.5×10×t 2 ) ⟹t 2 −5t−14=0 Solving above quadratic equation, we get t=−2,7 As time is always positive, t=7s |
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