1.

A ball is thrown with a speed of 20 m si at an elevation angle 45°. Find its time of flight and the horizontal range (take g = 10 m s-?​

Answer»

Answer:

TIME = 2root2sec , Range = 40m

Explanation:

time \: of \: \: flight (t) = \frac{2usin \alpha }{g} \\ given \: it \: u = 20m {s}^{ - 2} \\ \ \: \: \: \: \: \: \: \: \alpha = {45}^{0} \\ t = \frac{2 \times 20 \times sin {45}^{0} }{10} \\ t = 4 \times \frac{1}{ \sqrt{2} } s \\ t = 2 \sqrt{2} s \: \\ range = \frac{ {u}^{2}sin2 \alpha }{g } \\ range = \frac{20 \times 20 \times sin {90}^{0} }{10} \\ range = 40m

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