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A ball is thrown vertically upwards with velocity 50m/s at t=0. Find the distance travelled from t=0 to t=8s |
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Answer» Answer: Explanation: Velocity of the BALL = u=50m/s (Given) Time = t = 0 (Given) Distance travelled from t = 0 to t = 8 - ? a = -10 According to the SECOND equation of motion - s = ut+1/2at² Thus, SUBSTITUTING the value - s = 50 × 0 + 1/2 × (-10) × 0 s = 0 Now, again,u=50m/s , a = -10, and t=8sec s = ut+1/2at² Thus, substituting the value - s = 50 × 8 + 1/2 × -10 × 8² s = 400-320 s = 80 Thus, the distance travelled from t = 0 to t = 8s is 80m. |
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