A ball is thrown vertically upwards with a velocity of 25 ms from the

1.	A ball is thrown vertically upwards with a velocity of 25 ms from the top of a tower ol height 30 m. How long will it travel before it hits ground 6s (2) 5
Answer» Answer: t = 3 sec Explanation: Given ; Initial VELOCITY ( u ) = 25 m / sec Height ( h ) = 30 m Final velocity will be 0 m / sec we have to find time ( t ) From second equation of MOTION we have h = u t - 1 / 2 g t² [ ACCELERATION against gravity ] putting values [ Here displacement will be in negative ] - 30 = 25 t - 1 / 2 × 10 × t² [ Taken g = 10 ] - 30 = 25 t - 5 t² - 6 = 5 t - t² t² - 5 t - 6 = 0 ( t - 3 ) ( t + 2 ) = 0 t = 3 sec or t = - 2 sec . Time can't in negative ; Thus we get time t = 3 sec .

A ball is thrown vertically upwards with a velocity of 25 ms from the top of a tower ol height 30 m. How long will it travel before it hits ground 6s (2) 5

Answer»

Answer:

t = 3 sec

Explanation:

Given ;

Initial VELOCITY ( u ) = 25 m / sec

Height ( h ) = 30 m

Final velocity will be 0 m / sec

we have to find time ( t )

From second equation of MOTION we have

h = u t - 1 / 2 g t² [ ACCELERATION against gravity ]

putting values

[ Here displacement will be in negative ]

- 30 = 25 t - 1 / 2 × 10 × t² [ Taken g = 10 ]

- 30 = 25 t - 5 t²

- 6 = 5 t - t²

t² - 5 t - 6 = 0

( t - 3 ) ( t + 2 ) = 0

t = 3 sec or t = - 2 sec .

Time can't in negative ;

Thus we get time t = 3 sec .

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