A ball is thrown vertically upwards, with a speed of U. Equation of height as a function of t, is given by h = ut - (1/2)g(t^2). Find:1. Time to reach maximum height (t)2. Maximum height reached (h).g is the acceleration due to gravity. Answer is desired in terms of g (dont take its value).

A ball is thrown vertically upwards, with a speed of U. Equation of he

1.	A ball is thrown vertically upwards, with a speed of U. Equation of height as a function of t, is given by h = ut - (1/2)g(t^2). Find:1. Time to reach maximum height (t)2. Maximum height reached (h).g is the acceleration due to gravity. Answer is desired in terms of g (dont take its value).
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A ball is thrown vertically upwards, with a speed of U. Equation of height as a function of t, is given by h = ut - (1/2)g(t^2). Find:1. Time to reach maximum height (t)2. Maximum height reached (h).g is the acceleration due to gravity. Answer is desired in terms of g (dont take its value).​

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A ball is thrown vertically upwards, with a speed of U. Equation of height as a function of t, is given by h = ut - (1/2)g(t^2). Find:1. Time to reach maximum height (t)2. Maximum height reached (h).g is the acceleration due to gravity. Answer is desired in terms of g (dont take its value).